0.08x+x^2=-0.0016

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Solution for 0.08x+x^2=-0.0016 equation: 



0.08x+x^2=-0.0016

We move all terms to the left:

0.08x+x^2-(-0.0016)=0

We add all the numbers together, and all the variables

x^2+0.08x+0.0016=0

a = 1; b = 0.08; c = +0.0016;
Δ = b2-4ac
Δ = 0.082-4·1·0.0016
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-0.08}{2}=-0.08/2$

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